秒表的protues仿真图和程序

Question

用AT89C51设计一个2位的LED数码显示作为“秒表”：显示时间为00—99秒，每秒自动加1，另设计一个“开始”键和一个“复位”键。 汇编程序，protues仿真截图，最好有程序说明。。。

Answer 1

#include <reg52.h>

#define uchar unsigned char

#define uint unsigned int

sbit K1 = P3^7;

uchar i,Second_Counts,Key_Flag_Idx;

bit Key_State;

uchar DSY_CODE[]=

{

  0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f

};

void DelayMS(uint ms)

{

  uchar t;

while(ms--)

{

for(t=0;t<120;t++);

}

}

void Key_Event_Handle()

{

  if(Key_State == 0)

{

Key_Flag_Idx=(Key_Flag_Idx+1)%3;

switch(Key_Flag_Idx)

{

case 1:EA=1;ET0=1;TR0=1;break;

case 2:EA=0;ET0=0;TR0=0;break;

case 0:P0=0x3f;P2=0x3f;i=0;Second_Counts=0;

}

}

}

void main()

{

  P0 = 0x3f;

P2 = 0x3f;

i = 0;

Second_Counts = 0;

Key_State = 1;

TMOD = 0x01;

TH0  = (65535-50000)/256;

TL0  = (65535-50000)%256; 

while(1)

{

if(Key_State != K1)

{

DelayMS(10);

Key_State = K1;

Key_Event_Handle();

}

}

}

void DSY_Refresh() interrupt 1

{

  TH0  = (65535-50000)/256;

TL0  = (65535-50000)%256;

if(++i==2)

{

i = 0;

++Second_Counts;

P0 = DSY_CODE[Second_Counts/10];

P2 = DSY_CODE[Second_Counts%10];

if(Second_Counts == 100) Second_Counts = 0;

}

}