主程序根据具体情况，要求用户输入参数，然后调用。
// 已知dx,dy 是长，宽
double area1(double dx, double dy)
{
return dx * dy;
}
// 已知[x0,y0] [x1,y1] 平面上矩形对角点
double area2(double x0, double y0,double x1, double y1)
{
return (x1-x0) * (y1-y0);
}
// 空间矩形，已知4角点座标x0,y0,z0,x1,y1,z1,x2,y2,z2,x3,y3,z3
#include <math.h>
double area3(double x0,double y0,......)
{
double dx,dy;
dx = sqrt( (x1-x0)*(x1-x0) + (y1-y0)*(y1-y0) + (z1-z0) * (z1-z0) );
dy = sqrt( (x2-x0)*(x2-x0) + (y2-y0)*(y2-y0) + (z2-z0) * (z2-z0) );
return dx*dy;
}
#include<conio.h>
using namespace std;
double MianJi(double x,double y);
void main()
{
double x,y;
cout<<"请输入长:";
cin>>x;
cout<<"请输入宽:";
cin>>y;
double mianji=MianJi(x,y);
cout<<"面积是:"<<mianji<<endl;
}
double MianJi(double x,double y)
{
return x*y;
}
x和y是长宽
不努力，不自己动手在这饭碗上是很难有成就的。
基础需要自己去扎实。
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