Dim i As Integer, j As Integer, x(4, 4) As Integer
Dim s() As String
Dim ss() As String
s = Split(Text1.Text, Chr(13) & Chr(10))
For i = 0 To 4
ss = Split(s(i))
For j = 0 To 4
x(i, j) = Val(ss(j))
Next
Next
求关于vb怎么把文本框里输入的矩阵读入一个二维数组中保存下来
楼主可参考如下代码:Dim i As Integer, j As Integer, x(4, 4) As Integer Dim s() As String Dim ss() As String s = Split(Text1.Text, Chr(13) & Chr(10))For i = 0 To 4 ss = Split(s(i))For j = 0 To 4 x(i, j) = Val(ss(j))Next Next ...
在vb中,如何把文本文档中的数据读入到二维数组中,并且使二维数组的下...
Private Sub Form_Click()Dim temp As String, str As String Dim w1 As Integer, w2 As Integer '维数 Dim a() As Integer, b() As Integer Dim i As Integer, j As Integer, k As Integer w1 = 0 w2 = 0 Me.Text1.Text = "矩阵的初始状态为："+ vbCrLf Me.Text2.Text = "...
vb中如何把文本中的矩阵导入并使用
用Line Input语句，循环从文件里读出“行数”个字符串，每个字符串用Split()函数（delimiter参数输入" "空格）分割为“列数”个字符串数组，循环将每个字符串数组的元素类型转换为数值（Cint或Csng之类的函数）复值到二维数组的每列，如此嵌套2层循环即可。
VB 把一个m行n列矩阵中的元素存放到一个二维数组中,并求出该数组的平 ...
dim i as Integer dim j as integer dim m as integer dim n as integer dim x as integer m=4 '设4行 n=3 '设3列 redim d(m,n) as integer x=1 for i=1 to m for j=1 to n d(i,j)=x x=x + 1 next j next i '求平均值，最大值，最小值 dim MyAve as ...
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列数不定不好办啊，无法形成矩阵，可以行数不定，但列数必须固定
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Private Sub Command1_Click()Dim i As Integer, j As Integer, a(6, 6) As IntegerFor i = 1 To 6 For j = 1 To 6 Randomize a(i, j) = Fix(Rnd * 10) Print a(i, j); Next PrintNextPrintFor i = 1 To 6 For j = 1 To 6 Print i & ...
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1、打开前面板，在控制板中选择数组矩阵库中的数组放到前面板上。2、打开后面板，找到对应的数组。然后右键菜单中点击属性。3、默认的数组的属性为1维的，我们将其改为2。4、再次回到前面板，在数值库中，将数值插入控件拖入二维数组中的灰色区域。5、此时前面板中，数组的形状发生了变化。6、此时点...
vb 生成随机数矩阵 如何把矩阵的数据输入到listbox控件里,急求啊...
Private Sub Command2_Click()List1.Clear Dim i As Integer, j As Integer, a(1 To 5, 1 To 5) As Integer Dim cLine As String Randomize For i = 1 To 5 cLine = ""For j = 1 To 5 a(i, j) = Int(Rnd * (100 - 0 + 1) + 0)cLine = cLine & Space(5 - Len(...
VB中怎样对一个二维数组的行进行操作
通常，数学上的行列式或者矩阵，用二维数组来存放数据，二维数组的第1维，就是映射矩阵的行，二维数组的第2维，就是映射矩阵的列。例如：dim d(1 To 3,1 To 4) As Integer 对应的矩阵就是 d(1,1)d(1,2)d(1,3)d(1,4)d(2,1)d(2,2)d(2,3)d(2,4)d(3,1)d(3,2)d(...
...我想用VB编一个程序,用文本框直接输入一个矩阵,代码是这样的,但是...
Private Sub Text1_KeyPress(KeyAscii As Integer)l = l + 1 ‘On Error Resume Next If KeyAscii = 32 Then ReDim a(i, j)a(i, j) = Mid(Val(Text1.Text), k, l - k)j = j + 1 n = l + 1 k = n ElseIf KeyAscii = 13 Then i = i + 1 j = 0 k = k + 1 ...
