设计一个函数，要用到void reverse(int a[ ],int n) 颠倒数组a的前n个元素的顺序

Question

麻烦用VC++的，VC的就不要再粘贴过来了

Answer 1

#include<iostream>
using namespace std;
void reverse(int *a,int n)
{
int i,t;
for(i=0;i<n/2;i++)
{
t=*(a+i);
*(a+i)=*(a+n-i-1);
*(a+n-i-1)=t;
}
}
int main()
{
int i,a[]={0,1,2,3,4,5,6,7,8,9};
reverse(a,10);
for(i=0;i<10;i++)
cout<<a[i]<<' ';
cout<<endl;
return 0;
}

Answer 2

#include <iostream>
using namespace std;
void reverse(int a[ ], int n)
{
unsigned int i = 0;
unsigned int mid = 0;
unsigned int endvalue = n;
if (n & 0x1 == 0)
{
mid = n >> 1;
}
else
mid =(n >> 1) + 1;;
for (i=0; i<mid && i < endvalue; ++i)
{
a[i] = a[i] ^ a[endvalue];
a[endvalue] = a[endvalue] ^ a[i];
a[i] = a[i] ^ a[endvalue];
--endvalue;
}
}

int main()
{
int arr[] = {0,1,2,3,4,5,6,7,8,9};
reverse(arr,5);
for (unsigned int i=0; i<sizeof(arr) / sizeof(int); ++i)
{
cout << arr[i] << '\n';
}
system("pause");
return 0;
}

Answer 3

int i,x;
for(i=0;i<n/2;i++) {x=a[i];a[i]=a[n-i];a[n-i]=x;}

话说，VC++和VC在这里有区别么。。