求解∫y/√1–y^2 dy=–∫dx

Question

求解∫y/√1–y^2 dy=–∫dx

Answer 1

∫y/√(1-y^2) dy=-∫dx
(1/2)∫d(1-y^2)/√(1-y^2) dy=∫dx
√(1-y^2) = x+C
1-y^2 =(x+C)^2
y=√[ 1-(x+C)^2]