帮我用MATLAB编个小程序，不胜感激

Answer 1

function p=moreThan2(n)
if n>365
p=1.0;
elseif (n<2)
p=0.0;
else
p=1-1.0*prod(365-n+1:365)/power(365,n);
end
format long;
end

for i=2:40
p=moreThan2(i)
end