C++ 定义一个数组，将里面的 十个数按从小到大的顺序排序并挑出奇数

Answer 1

int a[10];

for (int i = 0; i < 9; i++)
for (int j = i+1; j < 10; j++)
if (a[i]>a[j])
{
int t = a[i];
a[i] = a[j];
a[j] = t;
}

for (int i = 0; i < 10; i++)
{
cout<<a[i]<<" ";
if (a[i]%2==1) cout<<"this is odd";
}