已知1/x-1/y=3,求(3x+4xy-3y)/(x-2xy-y)的值

如题所述

1/x-1/y通分=(y-x)/xy=3
y-x=3xy
x-y=-3xy

所以原式=[3(x-y)+4xy]/[(x-y)-2xy]
=[3(-3xy)+4xy]/[(-3xy)-2xy]
=-5xy/(-5xy)
=1来自:求助得到的回答
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第1个回答  2010-10-08
天啊~~~您真是天才,你是不是事先就知道答案了,怎么这么厉害??无语。。。。。

已知1\/x-1\/y=3,求(3x+4xy-3y)\/(x-2xy-y)的值
1\/x-1\/y通分=(y-x)\/xy=3 y-x=3xy x-y=-3xy 所以原式=[3(x-y)+4xy]\/[(x-y)-2xy]=[3(-3xy)+4xy]\/[(-3xy)-2xy]=-5xy\/(-5xy)=1

已知1\/x-1\/y=3 求(2x+3xy-2y)\/(x-2xy-y)的值
解:由已知1\/x-1\/y=3可得:y-x=3xy x-y=-3xy 则:(2x+3xy-2y)\/(x-2xy-y)=(2x-2y+y-x)\/[x-y+2\/3(x-y)]=(x-y)\/[5\/3(x-y)]=1\/5\/3 =3\/5

若1\/X-1\/y=3,求分式x+4xy-y\/3x-2xy-3y的值
解:因为1\/X-1\/y=3 所以(y-x)\/xy=3,y-x=3xy x-y=-3xy 所以(x+4xy-y)\/(3x-2xy-3y)=【(x+y)+4xy】\/【3(x-y)-2xy】=【-3xy+4xy】\/【3*(-3xy)-2xy】=xy\/(-11xy)=-1\/11

【初二数学】1\/x-1\/y=3,则分式(4x+3xy-4y)\/(x-2xy-y)=___
y-x=3xy 原式=[3xy-4(y-x)]\/(x-y-2xy)=(3xy-12xy)\/(-3xy-2xy)=-9xy\/(-5xy)=9\/5

已知1\/x-(1\/y)=3,则2x+3xy-2y\/(x-2xy-y)的值是多少
已知:1\/x-1\/y=3,求(2x+3xy-2y)\/(x-2xy-y)解:由已知:1\/x-1\/y=3,即(y-x)\/xy=3,(y-x)=3xy x-y=-3xy (2x+3xy-2y)\/(x-2xy-y)=(-6xy+3xy)\/(-3xy-2xy)=-3xy\/(-5xy)=3\/5

已知1\/x-1\/y=3,求分式(4x-5xy-4y)\/(3x-2xy-3y)的值
解:由1\/x-1\/y=3知 x-y=3xy(x,y不等于0)即 4x-4y=12xy 3x-3y=9xy 则 (4x-5xy-4y)\/(3x-2xy-3y)=(12xy-5xy)\/(9xy-2xy)=7xy\/7xy =1 小朋友,题目要自己思考的,不能总是在网上找答案,要自己学会思考啊。加油啊!!!

已知,1\/ x-1\/y=3
因为1\/x-1\/y=(x-y)\/xy=3 所以,x-y=3xy 所以,(2x+3xy-2y)\/(x-2xy-y)=[2(x-y)+3xy]\/[(x-y)-2xy]=(2*3xy+3xy)\/(3xy-2xy)=9xy\/xy =9

若1\/x-1\/y=3,则分式2x+3xy-2y\/x-2xy-y 的值为多少
解:1\/x-1\/y=3 原式明显是需要假约分,分子分母同时除以xy得(2\/y+3-2\/x)\/(1\/y-2-1\/x)=(-6+3)\/(-3-2)=(-3)\/(-5)=0.6 为你解答,如有帮助请采纳,如对本题有疑问可追问,Good luck!

已知1\/x-1\/y=3,求分式2x+3xy-2y\/x-2xy-y的值
解:∵1\/x-1\/y=3 ∴y-x=3xy x-y=-3xy 2x+3xy-2y\/x-2xy-y =[2(x-y)+3xy]\/[(x-y)-2xy]=(-6xy+3xy)\/(-3xy-2xy)=-3xy\/(-5xy)=3\/5 如果你认可我的回答,请及时采纳!不懂可追问,采纳是对每一个回答者最真挚的感谢,谢谢合作!希望对你有帮助。

已知1\/x-1\/y=3,求3x-5xy-3y\/x-2xy-y的值.
声明楼主所求式子很可能表述不正确,如是(3x-5xy-3y)\/(x-2xy-y),解法如下。由已知x≠0,y≠0,故等式左右同乘以xy得 y-x=3xy 所求式子化为:原式=[3(x-y)-5xy]\/[(x-y)-xy]=[(-9xy)-5xy]\/[(-3xy)-xy]=14xy\/4xy=7\/2 ...

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