=1-1/2+1/4+1/8+1/16+1/32+1/64+1/128
=1-1/4+1/8+1/16+1/32+1/64+1/128
。。。。
=1-1/128
=127/128
所以原式=127/128本回答被提问者采纳
=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/128-1/128
=1/2+1/4+1/8+1/16+1/32+1/64++1/64-1/128
=1/2+1/4+1/8+1/16+1/32+1/32-1/128
=........
=1-1/128
=127/128
计算1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128怎么简便计算
原式=（1\/2+1\/4）+（1\/8+1\/16）+（1\/32+1\/64）+1\/128 =（2\/4+1\/4）+（2\/16+1\/16）+（2\/64+1\/64）+1\/128 =3\/4+3\/16+3\/64+1\/128 =3x(1\/4+1\/16+1\/64)+1\/128 =3x(16\/64+4\/64+1\/64)+1\/128 =3x(21\/64)+1\/128 =63\/64+1\/128 =126\/128+1\/128 =127...
计算1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128怎么简便计算
法一：原式+1\/128=1 所以原式=127\/128 法二：等比数列前n项和公式 1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128 =1\/2+(1\/2)^2+(1\/2)^3+……+(1\/2)^7 =1\/2×[1-(1\/2)^7]\/(1-1\/2)=1-(1\/2)^7 =1-1\/128 =127\/128 ...
计算1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128怎么简便计算
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128+1\/128-1\/128 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/64-1\/128 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/32-1\/128 =1\/2+1\/4+1\/8+1\/16+1\/16-1\/128 =1\/2+1\/4+1\/8+1\/8-1\/128 =1...
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128的简便运算
=(1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/64)-1\/128 =1-1\/128=127\/128 每一项后面的分母都是前面的一半，所以可以在原来的式子最后+1\/128，可以发现从后往前算,就是2个1\/128加起来变成1个1\/64，然后2个1\/64加起来变成1个1\/32，依次类推，最后就是2个1\/2加起来变成1。
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128
=1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128+1\/128-1\/128 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/64-1\/128 =1-1\/128 =127\/128 数学辅导团团员为您解答，有错误请指正，不明白请追问。没问题就采纳吧，真心希望能对你的学习或生活有所帮助！
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64怎样算简便
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =1-1\/64 =63\/64
计算1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128怎么简便计算
原式：1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128 =（1-1\/2）+（1\/2-1\/4）+（1\/4-1\/8）+（1\/8-1\/16）+（1\/16-1\/32）+（1\/32-1\/64）+（1\/64-1\/128）=1-1\/2+1\/2-1\/4+1\/4-1\/8+1\/8-1\/16+1\/16-1\/32+1\/32-1\/64+1\/64-1\/128 =1-1\/128……互相抵消 =...
简算:2分之1+4分之1+8分之1+16分之1+32分之1+64分之1+128分之1=?
根据等比数列求和公式，算得的结果为127\/128
1\/2+1\/4+1\/8,加1\/16+1\/32+1\/64简便计算?
1\/64+1\/64)-1\/64 =1\/2+1\/4+1\/8+1\/16+(1\/32+1\/32)-1\/64 =1\/2+1\/4+1\/8+(1\/16+1\/16)-1\/64 =1\/2+1\/4+(1\/8+1\/8)-1\/64 =1\/2+(1\/4+1\/4)-1\/64 =1\/2+1\/2-1\/64 =1-1\/64 =63\/64 中间的过程可以略写的，只是为了让你方便理解，才一步步写出 ...
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64的简便运算
=1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/64-1\/64 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/32-1\/64 =1\/2+1\/4+1\/8+1\/16+1\/16-1\/64 =1\/2+1\/4+1\/8+1\/8-1\/64 =1\/2+1\/4+1\/4-1\/64 =1\/2+1\/2-1\/64 =1-1\/64 =63\/64 希望帮到你 ...
