c语言编程训练

Question

1、 猜数游戏（掌握程序结构及随机函数应用）程序说明：游戏的开始由机器产生一个随机数（1-100之间），然后游戏者在程序的提示下猜数，若谅无同忧人数比这个数大，程序提示：Your answer is HIGHER, try again. ，否则，程序提示：Your answer is LOWER, try again. ，直到猜对为止。程序可实现连续猜数，直到游戏者退出。程序要求：累计游戏者猜对一个数所需的次数n。当n<=7时，给出“congratulation”字样；当7<n<15时，给出“You can do it better.”；当n>=15时，给出“I can’t bare it.”的提示，并退出程序。

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

static void guess(int number, int *count)
{
int n;
do
{
scanf("%d", &n);

if ( n > number )
{
printf("Your answer is HIGHER, try again.\n");
}else if ( n < number )
{
printf("Your answer is LOWER, try again.\n");
}
++*count;

}while ( n != number );
}

int main(int argc, char *argv[])
{
int number;
int count = 0;

srand((unsigned int) time(NULL));

while ( count < 15 )
{
number = rand()%100 + 1;
guess(number, &count);

if ( count <= 7 )
{
printf("congratulation.\n");
}

else if ( count > 7 && count <15 )
{
printf("You can do it better.\n");
}
}

printf("I can’t bare it.\n");
}