用23519这五个数字组成五位数一共可以组成多少个这样的五位数把这些数按从大?

如题所述

5个数字互不相同,一共可以组成 5!=120 个五位数。
从大到小排列如下:
95321,95312,95231,95213,95132,95123,93521,93512,93251,93215,93152,93125,92531,92513,92351,92315,92153,92135,91532,91523,91352,91325,91253,91235,59321,59312,59231,59213,59132,59123,53921,53912,53291,53219,53192,53129,52931,52913,52391,52319,52193,52139,51932,51923,51392,51329,51293,51239,39521,39512,39251,39215,39152,39125,35921,35912,35291,35219,35192,35129,32951,32915,32591,32519,32195,32159,31952,31925,31592,31529,31295,31259,29531,29513,29351,29315,29153,29135,25931,25913,25391,25319,25193,25139,23951,23915,23591,23519,23195,23159,21953,21935,21593,21539,21395,21359,19532,19523,19352,19325,19253,19235,15932,15923,15392,15329,15293,15239,13952,13925,13592,13529,13295,13259,12953,12935,12593,12539,12395,12359。
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第1个回答  2023-09-10
用 2,3,5,1,9 这五个数字组成没有重复数字的五位数,一共可以组成 5!= 120个,
从大到小是 95321, 95312, ...... , 12395, 12359

用23519这五个数字组成五位数一共可以组成多少个这样的五位数把这些数...
5个数字互不相同,一共可以组成 5!=120 个五位数。从大到小排列如下:95321,95312,95231,95213,95132,95123,93521,93512,93251,93215,93152,93125,92531,92513,92351,92315,92153,92135,91532,91523,91352,91325,91253,91235,59321,59312,59231,59213,59132,59123,53921,53912,...

...5组成三位数乘两位数的乘法算式,你能写出几个?你能写出乘积最大的...
6. 因此,乘积最大的算式是543 × 43 = 23519。

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