用c#编写创建一个控制台应用程序，求出1~1000之间的所有能被7整除的数，并计算和输出每5个的和。

Answer 1

int max = 0;
int y = 0;
for (int i = 1; i <= 1000; i++)
{
if (i % 7 == 0)
{
y++;

Console.WriteLine(y + " " + i);

max += i;

if (y % 5 == 0)
{
Console.WriteLine("count every five: " + max);
max = 0;
}
}

}

Answer 2

int sum = 0;
int count = 0;
for (int i = 1; i<= 1000; i++) {
if(i%7 == 0) {
sum += i;
count ++;
}
if(count > 1 && count%5 == 0) {
System.Console.WriteLine(sum);
sum = 0;
count = 0;
}
}