(x-y)^3(y-x)(y-x)^2+(x-y)^6=

请老师写出过程,谢谢。

原式=(x-y)^3[-(x-y)][-(x-y)]^2+(x-y)^6
=-(x-y)^3(x-y)(x-y)^2+(x-y)^6
=-(x-y)^6+(x-y)^6
=0
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第1个回答  2010-04-18
-(y-x)^3(y-x)(y-x)^2+(y-x)^6=0

(x-y)^3(y-x)(y-x)^2+(x-y)^6=
原式=(x-y)^3[-(x-y)][-(x-y)]^2+(x-y)^6 =-(x-y)^3(x-y)(x-y)^2+(x-y)^6 =-(x-y)^6+(x-y)^6 =0

(x-y)^3(y-x)^2·(y-x)·(x-y)^4
解:原式=(x-y)^4+x(x-y)^3+y(x-y)^3 =(x-y)^4+(x+y)(x-y)^3 =(x-y)^3((x-y)+(x+y)) =2x(x-y)^3

(x-y)^3(x-y)^2(y-x)


(X-Y)^3(X-Y)^2(Y-X)的计算结果
-(x-y)^6

(x-y)^3(x-y)^2(y-x)
解:原式=(x-y)³(x-y)²×[-(x-y)]=-(x-y)^(3+2+1)=-(x-y)^6

(x-y)^3(x-y)^2(y-x)
(x-y)^3(x-y)^2(y-x)=-(x-y)^6 请采纳正确答案,你们只提问,不采纳正确答案,回答都没有劲!谢谢管理员推荐采纳!!朋友,请【采纳答案】,您的采纳是我答题的动力,如果没有明白,请追问。谢谢。

(x —y )^3乘(y —x )^2
x减y的立方和y减x的立方相等,所以就是y减x的五次方

(x-y)^3x(x-y)^2x(y-x) 
解:依题意得,(x-y)的3次方×(x-y)的2次方×(y-x)=(x-y)的3次方×(x-y)的2次方×[-(x-y)]=-(x-y)的(3+2+1)次方 =-(x-y)的6次方 即(x-y)的3次方×(x-y)的2次方×(y-x)=-(x-y)的6次方 ...

(x-y)×(x-y)^3×(y-x)^2
=(x-y)^6

(x-y)^3•(y-x)^2•(x-y)^5
=(x-y)^8*(x-y)^2 =(x-y)^10 平方可以倒过来如(1-3)^2=(3-1)^2

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