求个简单的单片机程序，最好能有电路图

Question

不要跑马灯和LED顺序显示的那个了，多谢了

Answer 1

#include"reg51.h"

#defineuchar unsigned char

uchardisplay_code[]={0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,0x80,0x90,0x88,0x83,0xC6,0xA1,0x86,0x8E};

 

uchartime[]={0,0,0,0};

 

voiddelay05ms(void)

{

 uchar i;

 for(i=250;i>0;i--);

}

 

voiddisplay()

{

  uchar i,k;

  k=0x80;

  for(i=0;i<8;i++)

  {

  P2=0;

  P0=display_code[time[i]/10];

  P2=k;

  k=k>>1;

  delay();

P0=display_code[time[i]%10];

  P2=k;

  k=k>>1;

  delay();

}

  P2=0;

}

 

voidcalc()

{

time[2]++;

if(time[2]>59)

{

time[2]=0;

time[1]++;

if(time[1]>59)

{

time[1]=0;

time[0]++;

if(time[0]>23)

{

time[0]=0;

}

}

}

 

voidmain(void)

{

uchari;

while(1)

{

for(i=0;i<250;i++)

{

display();

}

calc();

}

}

简易电子时钟。。

追问

这个不错，是51单片机的吗，如果能解释下代码就好了，抱歉，我是小白

追答

#include"reg51.h" //包含的库文件
#define uchar unsigned char //定义常量 uchar代表unsigned char
uchardisplay_code[]={0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,0x80,0x90,0x88,0x83,0xC6,0xA1,0x86,0x8E};
//上面这行定义是共阳极数码管显示0-9，A-F
uchartime[]={0,0,0,0}; //定义中间就是，用于计算时分秒

voiddelay05ms(void) // 这个函数定义0.5s左右的时间
{
uchar i;
for(i=250;i>0;i--);
}

voiddisplay() //这是显示的程序
{
uchar i,k;
k=0x80; //
for(i=0;i>1;//移到下一位显示，以下类同
delay();
P0=display_code[time[i]%10];
P2=k;
k=k>>1;
delay();
}
P2=0;
}

voidcalc()//这是上电后计算时分秒之关系
{
time[2]++;//秒加1
if(time[2]>59)//当秒大于59时
{
time[2]=0;//秒等于0
time[1]++;//分钟加1
if(time[1]>59) //分大于59时
{
time[1]=0;//分钟为0
time[0]++;//小时加1
if(time[0]>23) //小时大于23时，
{
time[0]=0;//小时为0
}
}
}

voidmain(void) //主函数
{
uchari;
while(1)
{
for(i=0;i<250;i++)
{
display(); //调用显示程序
}
calc();//调用计算函数
}
}

Answer 2

1602显示
#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
uchar code table[]="1234567890";
//uchar code table1[]="0987654321";
sbit RS = P2^4; //定义端口
sbit RW = P2^5;
sbit EN = P2^6;
int num;

void delay(uint z) //延时
{
uint x,y;
for(x=z;x>0;x--)
{
for(y=110;y>0;y--);
}
}

void write_com(uchar com) //写命令
{
RS=0;
P0=com;
delay(5);
EN=1;
delay(5);
EN=0;
}
void write_date(uchar date)
{
RS=1;
P0=date;
delay(5);
EN=1;
delay(5);
EN=0;
}
void init()
{
RW=0; //必须写0
write_com(0x38);
write_com(0x0c);
write_com(0x06);
write_com(0x01);
}
main()
{
init();
while(1)
{
write_com(0x80+1);
for( num=0;num<10;num++)
{
write_date(table[num]);
delay(5);
}
}
}

Answer 3

#include <reg51.h>
unsigned long count = 0;
unsigned long show_count = 0;

unsigned char digest[11] = {0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x83,0xF8,0x80,0x98,0xC6};
unsigned char scancode[8] = {0x1,0x2,0x4,0x8,0x10,0x20,0x40,0x80};

sbit P1_0 = P1^0;

#define HIGH_BIT 0xFB
#define LOW_BIT 0x80

void Disp(int id)
{
P2 = 0;
P2 = scancode[id];
P0 = 0xff;
switch (id)
{
case 0: P0 = digest[(show_count / 10000000) % 10]; break;
case 1: P0 = digest[(show_count / 1000000) % 10]; break;
case 2: P0 = digest[(show_count / 100000) % 10]; break;
case 3: P0 = digest[(show_count / 10000) % 10]; break;
case 4: P0 = digest[(show_count / 1000) % 10]; break;
case 5: P0 = digest[(show_count / 100) % 10]; break;
case 6: P0 = digest[(show_count /10) % 10]; break;
case 7: P0 = digest[show_count % 10]; break;
}
}

void Timer0() interrupt 1
{
static unsigned int scount = 0;
static unsigned char rcount = 0;
TH0 = HIGH_BIT;
TL0 = LOW_BIT + 34;
scount++;

if (scount == 800) //1 second
{
scount = 0;
show_count = count;
count = 0;
}else if (scount % 2 == 0)
{
rcount++;
if (rcount == 8) rcount = 0;
Disp(rcount);
}

count += (TH1 << 8) | TL1;
TH1 = TL1 = 0;
}

void main()
{
TMOD = 0x51;
// 11.0592 Mhz 1.152 ms
TH0 = HIGH_BIT;
TL0 = LOW_BIT;
//initalize output counter
TH1 = 0;
TL1 = 0;

EA=1;
ET0=1;
TR0=1;
TR1=1;

for (;;);
}
请采纳。

Answer 4

你要什么图？proteus的还是DXP的？

追问

我是小白，就像楼上的就好