1/(y-y^2)求积分

Answer 1

1/(y-y^2)=1/y+1/(1-y)
∫1/(y-y^2)*dy=∫1/ydy+∫1/(1-y)dx
=∫1/ydy-∫1/(1-y)d(1-y)
=lnlyl-lnl1-yl
=lnly/(1-y)l+c

追问

第一步那不应该是乘吗？

追答

1/(y-y^2)=1/y(1-y)=1/y+1/(1-y)

追问

谢了