利用递归的方法求一个实数数组中所有元素的平均值

Answer 1

#include<stdio.h>
#include<stdlib.h>

int main()
{
int i,n,total=0,ave,a[n];
printf("please input the total num:");
scanf("%d",&n);
printf("please input the mark:");
for(i=0;i<n;i++)
scanf("%d",&a[i]);

for(i=0;i<n;i++)
total+=a[i];
printf("%d",total);
ave=total/n;
printf("ave=%d",ave);
system("pause");
}

Answer 2

//---------------------------------------------------------------------------

#include <stdio.h>
#define AVE(A,B) aver(A,B,0)

double aver(float *a,int n,int t)
{

if (t!=n) return (a[t]/n+aver(a,n,t+1));
else return 0;

}
int main(void)
{
float a[]={1,5,9,13,17};
printf("%f",AVE(a,5));
return 0;
}
//---------------------------------------------------------------------------