c++编程；用if语句实现从键盘输入3个整数按从大到小的顺序输出。

Answer 1

#include <iostream.h>
void main()
{
int a,b,c,t;
cout<<"输入3个整数:";
cin>>a>>b>>c;
if(a<b)
{
t=a;a=b;b=t;
}
if(b<c)
{
t=b;b=c;c=t;
}
if(a<b)
{
t=a;a=b;b=t;
}
cout<<a<<' '<<b<<' '<<c<<endl;
}

Answer 2

源程序如下：#include <iostream>
using namespace std;
int main()
{
int x,y,z,j;
cout<<"输入三个数字,中间用空格隔开\n";
cin>>x>>y>>z;
if(x<y)
{
j=x;x=y;y=j;
}
if(x<z )
{
j=x; x=z;z=j;
}
if(y<z)
{
j=y;y=z; z=j;
}
cout<<x<<','<<y<<','<<z<<endl;
return 0;
}VC++6.0测试如下：

Answer 3

input a,b,c;
if(a<b){t=a; a=b;b=t;}
if(a<c){t=a; a=c;c=t;}
if(b<c){t=b; b=c;c=t;}
output a,b,c;

Answer 4

#include <stdio.h>
void swap(int* a, int* b)
{
if(!a || !b)return;
int tmp;
tmp=*a;
*a=*b;
*b=tmp;
}
void main()
{
int a,b,c;
scanf("%d%d%d", &a, &b, &c);
if(a>b)swap(&a, &b);
if(a>c)swap(&a, &c);
if(b>c)swap(&b, &c);
printf("%d\t%d\t%d\n", a, b, c);
}