编写程序,求e的值.e≈1+1/1!+1/2!+1/3!+1/4!+···+1/n! (1)用for循环,计算前30项;

Answer 1

#include"stdio.h"
int mul(int n){
if(n==1){
return 1;
}
else{
return n*mul(n-1);
}
}
float func(int n){
return 1.0/mul(n);
}

int main(){
float e = 1.0;
int i = 1;
for(i = 1;i<=30;i++){
e += func(i);
}
printf("%lf\n",e);
return 0;
}