c语言循环简易计算器

Question

main()
{ float a,b,y;
char c;
printf("Please enter:\n");
scanf("%f%c%f",&a,&c,&b);
switch(c)
{case'+':printf("%f%c%f=%f",a,c,b,a+b);break;
case'-':printf("%f%c%f=%f",a,c,b,a-b);break;
case'*':printf("%f%c%f=%f",a,c,b,a*b);break;
case'/':printf("%f%c%f=%f",a,c,b,a/b);break;
default:printf("wrong");break;
}
printf(" \n") ;
printf("Whether to continue?(y/n)\n ") ;

getch();
}
接下来怎么编，才能让它在y或者n中选择后进行循环？
选y则进行下一次计算，n为直接退出。

Answer 1

根本不需要那么复杂
#include <stdio.h>
#include <conio.h>
main()
{
float a,b,y;
char c,ch;
printf("Please enter:\n");
scanf("%f%c%f",&a,&c,&b);
switch(c)
{
case'+':printf("%f%c%f=%f",a,c,b,a+b);break;
case'-':printf("%f%c%f=%f",a,c,b,a-b);break;
case'*':printf("%f%c%f=%f",a,c,b,a*b);break;
case'/':printf("%f%c%f=%f",a,c,b,a/b);break;
default:printf("wrong");break;
}
printf(" \n") ;
printf("Whether to continue?(y/n)\n");
fflush(stdin); //清空缓冲区
ch=getchar(); //接收输入字符
if (ch=='Y' || ch=='y') //判断输入字符并进行继续或者退出操作
{
printf("继续\n");
main(); //返回main函数
}
else
printf("退出！\n"); //什么也不做 自然退出
}

Answer 2

main()
{ float a,b,y;
char c;
printf("Whether to continue?(y/n)\n ") ;
if(getch()=='y')
calc();
else
return;
}
void calc()
{
printf("Please enter:\n");
scanf("%f%c%f",&a,&c,&b);
switch(c)
{case'+':printf("%f%c%f=%f",a,c,b,a+b);break;
case'-':printf("%f%c%f=%f",a,c,b,a-b);break;
case'*':printf("%f%c%f=%f",a,c,b,a*b);break;
case'/':printf("%f%c%f=%f",a,c,b,a/b);break;
default:printf("wrong");break;
}
printf(" \n") ;
}

Answer 3

main()
{ float a,b,y;
char c;
while(1)
{

char s;

printf("Please enter:\n");
scanf("%f%c%f",&a,&c,&b);
switch(c)
{
case'+':printf("%f%c%f=%f",a,c,b,a+b);break;
case'-':printf("%f%c%f=%f",a,c,b,a-b);break;
case'*':printf("%f%c%f=%f",a,c,b,a*b);break;
case'/':printf("%f%c%f=%f",a,c,b,a/b);break;
default:printf("wrong");break;
}
printf(" \n") ;
printf("Whether to continue?(y/n)\n ") ;
if(getch(s)=='n')
break;
}
getch();
}

Answer 4

#include<stdio.h>
#include<string.h>

main()
{ float a,b,y;
char c;
do{
printf("Please enter:\n");
scanf("%f%c%f",&a,&c,&b);
switch(c)
{case'+':printf("%f%c%f=%f",a,c,b,a+b);break;
case'-':printf("%f%c%f=%f",a,c,b,a-b);break;
case'*':printf("%f%c%f=%f",a,c,b,a*b);break;
case'/':printf("%f%c%f=%f",a,c,b,a/b);break;
default:printf("wrong");break;
}
printf(" \n") ;
printf("Whether to continue?(y/n)\n ") ;
}while(getch()=='y');
}