c程序:输入一行字符,统计其中英文字母,数字,空格,其他字符的个数(要求随便输几个字符都能知道个数)

Question

就是随便打一行字符,回车后知道个数,不限制字符数

Answer 1

#include <stdio.h>
#include <string.h>
int main(int argc,char *argv[])
{
int letters = 0;
int nums = 0;
int spaces = 0;
int others = 0;
char line[1024];
char *p;
printf("Please input one line string:");
p = fgets(line,1023,stdin);
if(p == NULL) return ;
while(*p)
{
if((*p >= 'a' && *p <= 'z') || (*p >= 'A' && *p <= 'Z'))
letters++;
else if(*p == ' ') spaces++;
else if(*p >= '0' && *p <= '9') nums++;
else others++;
p++;
}
printf("input:%s\n",line);

printf("letters:%d,numbers=%d,space=%d,other=%d\n",letters,nums,spaces,others);
}