利用C/C++将十进制数转换为十六进制。用到堆栈。我完成了2、8进制转换，16进制有ABCDEF字母，求帮助

Question

#include <stdio.h>
#include <stdlib.h>
#define STACK_INIT_SIZE 100
#define STACKINCREAMENT 10

typedef struct
{
int *base;
int *top;
int stacksize;
} SqStack;
void InitStack(SqStack*);
int StackEmpty(SqStack*);
void Push(SqStack*,int);
int Pop(SqStack*,int *);
void InitStack(SqStack *s)
{
s->base=(int*)malloc((STACK_INIT_SIZE)*sizeof(int));
if(!s->base) exit(0);
s->top=s->base;
s->stacksize=STACK_INIT_SIZE;
}
int StackEmpty(SqStack *s)
{
if(s->top==s->base)
return 1;
else
return 0;
}
void Push(SqStack *s,int e)
{
if(s->top-s->base>=s->stacksize)
{
s->base=(int*)realloc(s->base,(s->stacksize+STACKINCREAMENT)*sizeof(int));
if(!s->base) exit(0);
s->top=s->base+s->stacksize;
s->stacksize+=STACKINCREAMENT;
}
*(s->top) = e;
s->top++;
}
int Pop(SqStack *s,int *e)
{
if(s->top==s->base)
return 0;
else
e=--s->top;
return * e;
}
void main()
{
SqStack s;
int e,m,n;
InitStack(&s);
scanf("%d%d",&m,&n);
while(m)
{
Push(&s,m%n);
m=m/n;
}
while(!StackEmpty(&s))
printf("%d",Pop(&s,&e));
if(n==2)
printf("B\n");
else if(n==8)
printf("Q\n");
if(n==16)
{ switch(e)
{ case 10:printf("A");break;
case 11:printf("B");break;
case 12:printf("C");break;
case 13:printf("D");break;
case 14:printf("E");break;
case 15:printf("F");break;
default :printf("error");}
}
}
这是我的源程序

Answer 1

printf("%02X\n", num);

OR
char HexStr[]="0123456789ABCDEF";

printf("%c%c", HexStr[num>>28 & 0xf], HexStr[num>>24 & 0xf]);
......

Answer 2

针对有ABCDEF的字符问题，可以另辟一个字符堆栈来解决。

Answer 3

输出字符: num-10+'A'

Answer 4

你要帮助什么？程序有错找不到？