C语言编好的程序一闪而过，怎么不一闪而过？ 已经加了# include<stdlib.h>和system（“pause”）；

Question

我是初学者，麻烦知道的提醒一下啊！
# include <stdio.h>
# include <math.h>
# include <bios.h>
# include <conio.h>
# include <stdlib.h>
int main(void)
{
int choice,money;
float sum;
do{
clrscr();
textcolor(RED);
gotoxy(13,3);
printf("\xDB\xDB\xDB\xDB\xB2 INTEREST CALCULATOR \xB2\xDB\xDB\xDB\xDB");
gotoxy(2,9);
printf("Choose Year 1：one year; 2：two year; 3:three year");
gotoxy(2,10);
printf(" 4: five year; 5: eight year; 0: exit\n");
printf("Please choose years deposits : \n");
scanf("%d",&choice);

switch(choice)
{
case 1:{
float one_year(float money);
printf("Please input the amount of deposit :");
scanf("%f",&money);
sum=one_year(money);
break;
}
case 2:{
float two_year(float money);
printf("Please input the amount of deposit :");
scanf("%f",&money);
sum=two_year(money);
break;
}
case 3:{
float three_year(float money);
printf("Please input the amount of deposit :");
scanf("%f",&money);
sum=three_year(money);
break;
}
case 4:{
float five_year(float money);
printf("Please input the amount of deposit :");
scanf("%f",&money);
sum=five_year(money);
break;
}
case 5:{
float eight_year(float money);
printf("Please input the amount of deposit :");
scanf("%f",&money);
sum=eight_year(money);
break;
}
case 0:break;
}
}while(choice!=0);
printf("%.3f",sum);
system("pause");
return 0;
}

float one_year(float money)
{
float sum,i,a;
a=1;
for(i=0;i<=12;i++){
a=a*1.0225;
}
sum=a*money;

return sum;

}

float two_year(float money)
{
float sum,a,i;
a=1;
for(i=0;i<=12;i++){
a=a*1.0243;
}
sum=a*money;
return sum;
}

float three_year(float money)
{
float sum,a,i;
a=1;
for(i=0;i<=12;i++){
a=a*1.0270;
}
sum=a*money;
return sum;
}

float five_year(float money)
{
float sum,a,i;
a=1;
for(i=0;i<=12;i++){
a=a*1.0288;
}
sum=a*money;
return sum;

}

float eight_year(float money)
{
float sum,a,i;
a=1;
for(i=0;i<=12;i++){
a=a*1.03;
}
sum=a*money;
return sum;

}
麻烦知道的人，帮我运行一下啊，然后告诉我为什么啊？谢谢啊！

Answer 1

一闪而过就是错了。
# include <stdio.h>
# include <math.h>
# include <conio.h>
# include <stdlib.h>
int main(void)
{
int choice,money;
int sum=0;
do{
clrscr();
textcolor(RED);
gotoxy(13,3);
printf("\xDB\xDB\xDB\xDB\xB2 INTEREST CALCULATOR \xB2\xDB\xDB\xDB\xDB");
gotoxy(2,9);
printf("Choose Year 1：one year; 2：two year; 3:three year");
gotoxy(2,10);
printf(" 4: five year; 5: eight year; 0: exit\n");
printf("Please choose years deposits : \n");
scanf("%d",&choice);

switch(choice)
{
case 1:{
int one_year(int money);
printf("Please input the amount of deposit :");
scanf("%d",&money);
sum+=one_year(money);
break;
}
case 2:{
int two_year(int money);
printf("Please input the amount of deposit :");
sleep(6);
scanf("%d",&money);
sum+=two_year(money);
break;
}
case 3:{
int three_year(int money);
printf("Please input the amount of deposit :");
sleep(6);
scanf("%d",&money);
sum+=three_year(money);
break;
}
case 4:{
int five_year(int money);
printf("Please input the amount of deposit :");
sleep(6);
scanf("%d",&money);
sum+=five_year(money);
break;
}
case 5:{
int eight_year(int money);
printf("Please input the amount of deposit :");
sleep(6);
scanf("%d",&money);
sum+=eight_year(money);
break;
}
case 0:break;
}
}while(choice!=0);
sleep(6);
printf("%.3d",sum);
system("pause");
return 0;
}

int one_year(int money)
{
int sum,i,a;
a=1;
for(i=0;i<=12;i++){
a=a*1.0225;
}
sum=a*money;

return sum;

}

int two_year(int money)
{
int sum,a,i;
a=1;
for(i=0;i<=12;i++){
a=a*1.0243;
}
sum=a*money;
return sum;
}

int three_year(int money)
{
int sum,a,i;
a=1;
for(i=0;i<=12;i++){
a=a*1.0270;
}
sum=a*money;
return sum;
}

int five_year(int money)
{
int sum,a,i;
a=1;
for(i=0;i<=12;i++){
a=a*1.0288;
}
sum=a*money;
return sum;

}

int eight_year(int money)
{
int sum,a,i;
a=1;
for(i=0;i<=12;i++){
a=a*1.03;
}
sum=a*money;
return sum;

}
//我看网上的回答，应该是float的问题，但不知如何解决！！！！

Answer 2

在return之前，用getchar();

追问

还是不行耶 选择数字后 ，然后提示输入存款金额，输入之后，就一闪没了

Answer 3

按Ctrl+F5运行试试。

Answer 4

把money变量改成float型呢？