定义一个递归函数int sum_of_square(int n)

Question

计算表达式：1^2+2^2+3^2+....+n^2的值。在主函数中输入n值，通过调用sum_of_square() 输出结果。

Answer 1

#include <stdio.h>
int sum_of_square(int n)
{
int sum=0;
if(n<=0)
sum=0;
else
sum=n*n+sum_of_square(n-1);
return sum;
}
int main()
{
int n;
printf("n=");
scanf("%d",&n);
printf("%d",sum_of_square(n));
return 0;
}

Answer 2

int sum_of_square(int n)
{
if (n<=0) return 0;
else return n*n+sum_of_squre(n-1);
}

Answer 3

int sum_of_square(int n)
{ int s=0;
for (int i=1;i++;i<=n)
{
s=s+i*i;
}
return s;
}