(2x+9/x+3)-(1/x-3)-(2/x)=2

解方程。怎么解不出来啊?

(2x+9)/(x+3)-1/(x-3)-2/x=2
(2x+6+3)/(x+3)-1/(x-3)-2/x=2
2+3/(x+3)-1/(x-3)-2/x=2
3/(x+3)-1/(x-3)-2/x=0
3/(x+3)=1/(x-3)+2/x
3/(x+3)=[x+2(x-3)]/[x(x-3)]
3/(x+3)=(3x-6)/[x(x-3)]
1/(x+3)=(x-2)/[x(x-3)]
(x+3)(x-2)=x(x-3)
x^2+x-6=x^2-3x
4x=6
x=3/2
检验,成立
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第1个回答  2008-03-21
x1=1,x2=3

(2x+9\/x+3)-(1\/x-3)-(2\/x)=2
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当x为何值时,代数式x+3分之2x+9-x分之2-x-3分之1的值等于2
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2\/x+2\/(x+3)+(x-2)\/(x+3)=1怎么算
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{X+3\/(2X+9)}-{(X-3)\/(1)}-{(X)\/(2)}=2 X等于多少啊?谢谢哥哥姐姐们了...
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(2-x)\/(x-3)-(1)\/(3-x)=2分式方程?
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(x²\/x-3+9\/3-x)÷x-1\/x²-2x+1化简?
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