如何用C语言编程求三个数中的最小值

Answer 1

#include"stdio.h"
#define MIN(a, b, c) (a) < (b)? ((a) < (c)? (a) : (c)) : ((b) < (c)? (b) : (c))
void main()
{
printf("%d\n", MIN(5, 6, 3 + 1));
}

Answer 2

#include <stdio.h>

int min(int a, int b)
{
if (a < b) return a;
return b;
}

int main()
{
int a = 7, b = 5, c = 3;
int numMin;
numMin = min(a, b);
numMin = min(numMin, c);
printf("min: %d\n", numMin);
return 0;
}

Answer 3

首先输入三个数值

两两对比，若其中一个数值小于其他两个数值，则为最小值

代码如下：

#include <stido.h>

int mian(){

int a,b,c;
printf("请输入三个值：");
scanf("%d%d%d",&a,&b,&c);
if(a<=b&&a<=c) printf("最小值=%d",a);
else if(c<=b&&c<=a) printf("最小值=%d",c);
else if(b<=a&&b<=c) printf("最小值=%d",b);
}