c语言怎么编写1*（1+2）*（1+2+3）*（1+2+3+4+...+10) 谢谢大家帮助。come on

Answer 1

#include<stdio.h>
void main()
{
int i,j;
int sum = 0;
unsigned long result = 1;
for(i=1; i<=10; i++)
{
for(j=1; j<=i; j++)
{
sum += j;
}
result *= sum;
sum = 0;
}
printf("%ul\n",result);
}

Answer 2

#include <iostream>
using namespace std;
// C++的
double add(double);
double multi(double,double);

double add(double n)
{
double sum = 0;
for (double i=1;i<=n;i++){
sum = sum + i;
}
return sum;
}

double multi(double x,double y)
{
return x*y;
}

void main()
{
double sum = 1;
for (double i=1;i<=10;i++){
sum = multi(sum,add(i));
}
cout<<sum;
}

Answer 3

#include "stdio.h"
void main()
{
int i,t=1,s=1;
for(i=2;i<=10;i++)
{
t=t+i;
s=s*t;
}
printf("%d\n",s);

}

Answer 4

#include "stdio.h"

int main()
{
float i,j,sum,k=1;
for(i=1;i<=10;i++)
{
sum=0;
for(j=1;j<=i;j++)
{
sum=sum+j;
}
k=k*sum;
printf("%f\n",k);
}

return 0;
}