(x-y)^3\/(y-x)^2过程
呵呵，因为(y-x)^2=(x-y)^2所以原式=(x-y)^5望采纳 谢谢 有任何不懂 请加好友 一一解答
(x-y)的3次方除以(y-x)的2次方等于多少
(x-y)^3\/(y-x)^2=(x-y)^3\/(x-y)^2=x-y
(x-y)^3-(y-x)^2 因式分解
所以原式=(x-y)^3-【-(x-y)】^2=(x-y)^3-(x-y)^2=(x-y)^2*（x-y-1）
(x-y)^3·(y-x)^2·(y-x)^5详细过程
(x-y)^3·(y-x)^2·(y-x)^5 =(x-y)^3·(x-y)^2·(y-x)^5 =(x-y)^5 *(y-x)^5 =-(x-y)^5*(x-y)^5 =-(x-y)^10
(x —y )^3乘(y —x )^2
x减y的立方和y减x的立方相等，所以就是y减x的五次方
(x-y)的3次方 乘以(y-x)的平方
(x-y)的3次方 乘以（y-x）的平方 =(x-y)的3次方 乘以(x-y)的平方 =(x-y)的3+2次方 =(x-y)的5次方
(x-y)^3+(y-x)^2
解: (x-y)^3+(y-x)^2 =(x-y)^3+(x-y)^2 =(x-y)^2 * (x-y+1)
(x-y)^3(y-x)(y-x)^2+(x-y)^6=
原式=(x-y)^3[-(x-y)][-(x-y)]^2+(x-y)^6 =-(x-y)^3(x-y)(x-y)^2+(x-y)^6 =-(x-y)^6+(x-y)^6 =0
(x-y)^3减(x-y)^2=?
因式分解，原式等于 （x-y）²（x-y-1）.~回答完毕~~结果仅供参考~~\\(^o^)\/~祝学习进步~~~
(x-y)^3(x-y)^2(y-x)
解：原式=(x-y)³(x-y)²×[-(x-y)]=-(x-y)^(3+2+1)=-(x-y)^6
