float sum (n) {
float sum = 0;
int i = 1;
for(; i <= n; i++) {
sum += ((float)i)/(i+1);
}
return sum;
}
main()
{
printf("%.2f\n", sum(20));
}本回答被网友采纳
for(int i=1;i<=20;i++)
{
sum+=1.0*i/(i+1);
}
{
float sum = .0;
for(int i = 0; i<20; ++i)
{
sum = sum + i/(float)i+1;
}
printf("%f", sum);
return 1;
}
c语言编写题: 使用循环语求1\/2+2\/3+3\/4+4\/5+6\/7+...+19\/20
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C语言程序设计1+2\/3+3\/5+4\/7+5\/9+...的前20项之和
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C语言,编写一程序输入一个正整数n,计算并输出s的前n项和,s=1\/2-2\/...
如果你不把flag 改为float型的话 运行的结果是 0哦
