= x( x + y )[ ( x - y ) - ( x + y ) ]
= x( x + y )[ x - y - x - y ]
= x( x + y )( -2y )
= -2xy( x + y )
或者
= -x( x + y )[ ( y - x ) + ( x + y ) ]
= -x( x + y )[ y - x + x + y ]
= -x( x + y )( 2y )
= -2xy( x + y )本回答被网友采纳
x(x+y)(x-y)-x(x+y)²
=x(x+y)[(x-y)-(x+y)]
=x(x+y)(x-y-x-y)
=-2xy(x+y)
x(x+y)(x-y)-x(x+y)^2因式分解
原式=x(x+y)[(x-y)-(x+y)]=x(x+y)(x-y-x-y)=-2xy(x+y)=-2×1\/2×1 =-1
因式分解x括号x+y括号乘以x-y括号减去x括号x+y括号的平方?
X(X+Y)(X-Y)-X(X+Y)²=(X+Y)[X(X-Y)-X(X+Y)]=(X+Y)X[X-Y-X-Y]=-2XY(X+Y)
当x(x+y)(x-y)-x(x+y)²进行因式分解,并求当x+y=1,xy=-1\/2时此式...
因式分解结果 x（x+y）（x-y）-x（x+y）²=x（x+y）[（x-y）-（x+y）]=-2xy(x+y)当x+y=1,xy=-1\/2时此式 等于-2*（-1\/2）*1=1
(x+y)²(x-y)-(x+y)(x-y)²请完整回答。。因式分解
原式=(x+y)(x-y)(x+y-x+y)=2y(x+y)(x-y)
因式分解:(x+y)(x-y)-x(x+y) 谢谢!
原式=x^2-y^2-x^2-xy =y^2-xy =y(y-x)
因式分解:(x+y)(x-y)-(x+y)²
（x+y)(x-y-x-y)=(x+y)(-2y)=-2y(x+y)请采纳，你的采纳是我上进的动力！可以追问，一直到懂！!
2(x-y)(x+y)-(x+y)^2因式分解
解：原式=3x^2-x^2+2xy =(x-3y)(x+y)方法：十字相乘
(x+y)(x-y)=x^2-y^2 是不是因式分解?
不是。这是乘法公式 而 x²-y²=(x+y)(x-y) 才是因式分解
x(x+y)(x-y)-x(x-y) 因式分解
你可以提取公因式x(x-y) 算得X(X-Y)(X+Y-1)
(x+y)(x-y)-(2x-y)^2 怎么因式分解
x^2-y^2-4x^2+4xy-y^2 =-3x^2+4xy =x(4y-3x)希望可以帮到你，满意请采纳
