第1个回答 2011-02-16
查找:select * from table1 where field1 like ’%value1%’ ---like的语法很精妙,查资料!
排序:select * from table1 order by field1,field2 [desc]
总数:select count * as totalcount from table1
求和:select sum(field1) as sumvalue from table1
平均:select avg(field1) as avgvalue from table1
最大:select max(field1) as maxvalue from table1
最小:select min(field1) as minvalue from table1