关于 数组 按照给定顺序排序问题。

Question

String[] arr1 = {"1","2","3","4","5","6","7","8","9","10"}
String[] arr2 = {"10","2","5","6","8","1"}
String[] arr3 = {"10","2","5","6","8","1","3","4","7","9"}
原始数组 arr1 按照 arr2 这个不完整的顺序排序，如果 arr2 里面没有的元素，直接放在最后面去。最后得到的结果是 arr3 这样的格式。

怎么处理呀？ 求大神给指点下！

Answer 1

public class Test
{
public static void main(String args[])
{
int[] arr = {4, 1, 2, 6, 3, 8, 9, 10, 7, 5};

for (int i = 0; i < 10; i++)
System.out.print(arr[i] + " ");
System.out.println();

for (int i = 0; i < 10 - 1; i++)
for (int j = 0; j < 10 - 1 - i; j++)
{
if (arr[j] > arr[j + 1])
{
int temp = arr[j];
arr[j] = arr[j + 1];
arr[j + 1] = temp;
}
}
for (int i = 0; i < 10; i++)
System.out.print(arr[i] + " ");
}
}

追问

给定的排序顺序要是不完整的。。。不过还是谢谢。