2x-1/2[x-1/2(x-1)]=2/3(x-1)
2x-1/2[x-1/2x+1/2]=2/3x-2/3
2x-1/2[1/2x+1/2]=2/3x-2/3
2x-1/4x-1/4=2/3x-2/3
7/4x-1/4=2/3x-2/3
7/4x-2/3x=1/4-2/3
13/12x=-5/12
x=(-5/12)÷(13/12)
x=-5/13
2x-1/4x-1/4=2/3x-2/3
7/4x-1/4=2/3x-2/3
7/4x-2/3x=1/4-2/3
13/12x=-5/12
x=(-5/12)÷(13/12)
x=-5/13
2x-1\/2[x-1\/2(x-1)]=2\/3(x-1)怎么算
2x-1\/2[x-1\/2(x-1)]=2\/3(x-1)2x-1\/2[x-1\/2x+1\/2]=2\/3x-2\/3 2x-1\/2[1\/2x+1\/2]=2\/3x-2\/3 2x-1\/4x-1\/4=2\/3x-2\/3 7\/4x-1\/4=2\/3x-2\/3 7\/4x-2\/3x=1\/4-2\/3 13\/12x=-5\/12 x=(-5\/12)÷(13\/12)x=-5\/13 ...
2x-1\/2[x-1\/2(x-1)=2\/3(x-1)怎么解
解：由题意可得：等式两边同时乘以6 12x-3(x-x\/2+1\/2)=4(x-1)12x-3x\/2-3\/2=4x-4 12x-4x-3x\/2=3\/2-4 13x\/2=-5\/2 x=-5\/13
2x-1\/2[x-1\/2(x-1)]=2\/3(x-1)
解：2x-1\/2［x-1\/2(x-1)］=2\/3(x-1)2x-1\/2(x-1\/2x+1\/2)=2\/3x-2\/3 2x-1\/2(1\/2x+1\/2)=2\/3x-2\/3 2x-1\/4x-1\/4=2\/3x-2\/3 7\/4x-1\/4=2\/3x-2\/3 7\/4x-2\/3x=1\/4-2\/3 21\/12x-8\/12x=3\/12-8\/12 13\/12x=-5\/12 x=-5\/13 ...
2x-1\/2[x-1\/2(x-1)]=2\/3(x-1)要过程
2x-1\/2（x-1\/2x+1\/2）=2\/3x-2\/3 2x-1\/2x+1\/4x-1\/4=2\/3x-2\/3 2x-1\/2x+1\/4x-2\/3x=-2\/3+1\/4 24\/12x-6\/12x+3\/12x-8\/12x=-8\/12+3\/12 13\/12x=-5\/12 x=-5\/12÷13\/12 x=-5\/13
2x-1\/2[x-1\/2(x-1)]=2\/3(x-1)
2x-1\/2[x-1\/2(x-1)]=2\/3(x-1)2x-1\/2x+1\/4x-1\/4=2\/3x-2\/3 乘12 24x-6x+3x-3=8x-8 24x-6x+3x-8x=-8+3 13x=-5 x=-5\/13
2x一1\/2[x一1\/2(x一1)]二2\/3(x一1)的解是
2x一1\/2[x一1\/2(x一1)]=2\/3(x一1)2x一1\/2[1\/2x+1\/2]=2\/3(x一1)2x一1\/4x一1\/4=2\/3x一2\/3 7\/4x-1\/4=2\/3x-2\/3 13\/12x=-5\/12 x=-5\/13
2x减去二分之一{X-二分之一(x-1)}=三分之二(x-1)
2x-1\/2[x-1\/2(x-1)]=2\/3(x-1)12x-3[x-1\/2x+1\/2]=4(x-1)12x-3x\/2-3\/2=4x-4 24x-3x-3=8x-8 24x-3x-8x=-8+3 13x=-5 x=-5\/13
2x-2分之1 [x- 2分之1(x-1)]= 3分之1(x-1)
2x—1\/2 [x—1\/2(x-1)]= 1\/3(x-1)解：2x—1\/2 [x—1\/2x＋1\/2)]= 1\/3(x-1)2x—1\/2 [1\/2x＋1\/2)]= 1\/3(x-1)2x—1\/4x—1\/4= 1\/3x—1\/3 7\/4X—1\/4= 1\/3x—1\/3 7\/4X—1\/3x=—1\/3＋1\/4 21\/12X—4\/12X=—4\/12＋3\/12 17\/12X=—1\/12 X=—...
解方程2x-1\/2[x-1\/2(x-1)]=1\/3(x-1)
2x-1\/2[x-1\/2(x-1)]=1\/3(x-1)则题目要求x不能为1 两边同时乘以6（x-1)化简得9（x-1\/2）^2=11\/4 3(x-1\/2)=+-√11\/2 x=1\/2+-√11\/6 根据我的步骤你自己来试试看，希望我的回答对你有帮助，谢谢！
2x-2分之1乘【x-2分之1乘(x+1)】=3分之2乘(x+1)
2x-1\/2[x-1\/2(x+1)]=2\/3(x+1)化简得13\/12x=5\/12 x=5\/13(x值为十三分之五)
