以下是用lingo写的程序，但不能运行，格式有错吗？请问错在哪里了？

Question

model:
sets:
number/1..32/:A,x,a,z;
endsets
max= @sum(number(j):(A(j)-1)*x(j)*a(j)) ;
@for(number(j):x(j)*(A(j)-1)<=z(j));
@for(number(j):@sum(number(j):A(j)<=180));
@for(number(j):x(j)>=0,a(j)>=0,A(j)>=0,z(j)>=0);
data:
x=60,15,35,10,12.5,75,7.5,90,100,50,110,30,40,37.5,40,25,15,12.5,25,25,30,15,15,40,10,30,35,40,60,75,22.5,40;
z=500,130,200,30,60,800,10,500,400,300,1000,80,1500,1000,500,300,200,100,700,2000,300,200,600,500,100,400,600,700,1000,3000,1500,1200;
enddata
end

Answer 1

错误很多 最好能自己仔细阅读lingo教程
1 lingo不区分大小写 所以你的A和a重名
2 倒数第二个约束括号位置错了
3 最后一个约束不必写 因为lingo默认变量非负 如果要写的话中间也应该是;而不是,
改成这样
model:
sets:
number/1..32/:A,x,a1,z;
endsets
max= @sum(number(j):(A(j)-1)*x(j)*a1(j)) ;
@for(number(j):x(j)*(A(j)-1)<=z(j));
@for(number(j):@sum(number(j):A(j))<=180);
data:
x=60,15,35,10,12.5,75,7.5,90,100,50,110,30,40,37.5,40,25,15,12.5,25,25,30,15,15,40,10,30,35,40,60,75,22.5,40;
z=500,130,200,30,60,800,10,500,400,300,1000,80,1500,1000,500,300,200,100,700,2000,300,200,600,500,100,400,600,700,1000,3000,1500,1200;
enddata
end

Answer 2

第二个for循环应该里面是@sum(number(j):A(j))<=180
你的括号打错了，导致sum函数里面有个不等式，所以错了。