C++编程题，要所有代码加注释，急求！

Question

编程实现一个计算人民币加减运算的程序，包含对人民币中的圆，角，分的计算。能正确的将分，角进位到元。要求必须使用面向对象编程的方法编程，使用类和运算符重载的知识。必须进行加减法和赋值两种运算。谢？~

Answer 1

#include<iostream>
using namespace std;
class Money
{
public:
Money(int pYuan=0, int pJiao=0, int pFen=0);
Money& operator + (Money& money);
Money& operator-(Money& money); //也可以用友元函数实现
void operator=(Money& money); //赋值运算符只能作为成员函数，而不能做友元函数
friend ostream& operator<<(ostream& output, Money& money);
private:
int yuan;
int jiao;
int fen;
};
Money::Money(int pYuan, int pJiao, int pFen)
{
yuan = pYuan;
jiao = pJiao;
fen = pFen;
}
Money& Money::operator +(Money& money)
{
int yuan;
int jiao;
int fen;
yuan = this->yuan + money.yuan;
jiao = this->jiao + money.jiao;
fen = this->fen + money.fen;
if(fen >= 10)
{
jiao += 1;
fen -= 10;
}
if(jiao >= 10)
{
yuan += 1;
jiao -= 10;
}
return Money(yuan, jiao, fen);
}

Money& Money::operator-(Money& money)
{
int yuan;
int jiao;
int fen;
fen = this->fen - money.fen;
if(fen < 0)
{
this->jiao -= 1;
fen += 10;
}
jiao = this->jiao - money.jiao;
if(jiao < 0)
{
this->yuan -= 1;
jiao += 10;
}
yuan = this->yuan - money.yuan;

return Money(yuan, jiao, fen);
}

void Money::operator=(Money& money)
{
yuan = money.yuan;
jiao = money.jiao;
fen = money.fen;
}
ostream& operator<<(ostream& output,Money& money)
{
output<<money.yuan<<"元"<<money.jiao<<"角"<<money.fen<<"分"<<endl;
return output;
}

void main()
{
Money money1(3,6,4);
Money money2(1,7,9);
Money money3;
Money money4;
Money money5;
money3=money1+money2;
money4=money1-money2;
money5=money4;
cout<<money3;
cout<<money4;
cout<<money5;
}
在VS2005中编译没问题，如果在VC6.0中有问题将头两行换为
#include<iostream.h>即可

追问

不能执，改成行#include出现这个错误warning C4172: returning address of local variable or temporary，但能执行，不过运行结果是错的

追答

把引用去掉：
#include
class Money
{
public:
Money(int pYuan=0, int pJiao=0, int pFen=0);
Money operator + (Money& money);
Money operator-(Money& money); //也可以用友元函数实现
void operator=(Money& money); //赋值运算符只能作为成员函数，而不能做友元函数
friend ostream& operatoryuan + money.yuan;
jiao = this->jiao + money.jiao;
fen = this->fen + money.fen;
if(fen >= 10)
{
jiao += 1;
fen -= 10;
}
if(jiao >= 10)
{
yuan += 1;
jiao -= 10;
}
return Money(yuan, jiao, fen);
}

Money Money::operator-(Money& money)
{
int yuan;
int jiao;
int fen;
fen = this->fen - money.fen;
if(fen jiao -= 1;
fen += 10;
}
jiao = this->jiao - money.jiao;
if(jiao yuan -= 1;
jiao += 10;
}
yuan = this->yuan - money.yuan;

return Money(yuan, jiao, fen);
}

void Money::operator=(Money& money)
{
yuan = money.yuan;
jiao = money.jiao;
fen = money.fen;
}
ostream& operator<<(ostream& output,Money& money)
{
output<<money.yuan<<"元"<<money.jiao<<"角"<<money.fen<<"分"<<endl;
return output;
}

void main()
{
Money money1(3,6,4);
Money money2(1,7,9);
Money money3;
Money money4;
Money money5;
money3=money1+money2;
money4=money1-money2;
money5=money4;
cout<<money3;
cout<<money4;
cout<<money5;
}