解方程(x-1\/x-2)+(x-7\/x-8)=(x-3\/x-4)+(x-5\/x-6)
(x-2+1)\/(x-2)+(x-8+1)\/(x-8)=(x-4+1)\/(x-4)+(x-6+1)\/(x-6)(此步对分子加1减1,是简便算法)1+1\/(x-2)+1+1\/(x-8)=1+1\/(x-4)+1+1\/(x-6)1\/(x-2)+1\/(x-8)=1\/(x-4)+1\/(x-6)1\/(x-8)-1\/(x-4)=1\/(x-6)-1\/(x-2)(此步移项成左右...
解方程(x-1\/x-2)+(x-7\/x-8)=(x-3\/x-4)+(x-5\/x-6)
(x-2+1)\/(x-2)+(x-8+1)\/(x-8)=(x-4+1)\/(x-4)+(x-6+1)\/(x-6) (此步对分子加1减1,是简便算法)1+1\/(x-2)+1+1\/(x-8)=1+1\/(x-4)+1+1\/(x-6)1\/(x-2)+1\/(x-8)=1\/(x-4)+1\/(x-6)1\/(x-8)-1\/(x-4)=1\/(x-6)-1\/(x-2) (此步移项...
解方程(x-1\/x-2)+(x-7\/x-8)=(x-3\/x-4)+(x-5\/x-6)
(x-2+1)\/(x-2)+(x-8+1)\/(x-8)=(x-4+1)\/(x-4)+(x-6+1)\/(x-6)(此步对分子加1减1,是简便算法)1+1\/(x-2)+1+1\/(x-8)=1+1\/(x-4)+1+1\/(x-6)1\/(x-2)+1\/(x-8)=1\/(x-4)+1\/(x-6)1\/(x-8)-1\/(x-4)=1\/(x-6)-1\/(x-2)(此步移项成左右相...
解方程:(x-5)\/(x-7)+(x-2)\/(x-4)=(x-3)\/(x-5)+(x-4)\/(x-6)
1-2\/(x-7)+1-2\/(x-4)=1-2\/(x-5)+1-2\/(x-6)2\/(x-7)+2\/(x-4)=2\/(x-5)+2\/(x-6)1\/(x-7)+1\/(x-4)=1\/(x-5)+1\/(x-6)(x-4+x-7)\/(x-4)(x-7)=(x-6+x-5)\/(x-5)(x-6)(2x-11)\/(x^2-11+28)=(2x-11)\/(x^2-11+30)因为x^2-11+28不等...
解分式方程:x-10\/x-8+x-6\/x-4=x-7\/x-5+x-9\/x-7
化简一下变成1-2\/(x-8)+1-2\/(x-4)=1-2\/(x-5)+1-2\/(x-7)由此可以看出1\/(x-8)+1\/(x-4)=1\/(x-5)+1\/(x-7)左右整合可以得到分子都为2x-12 所以分母相同x^2+32-12x=x^2+35-12x 很明显不对 所以分子为0 x=6 ...
解方程: (x-5)\/(x+7)+(x-2)\/(x-4)= (x-3)\/(x-5)+(x-4)\/(x-6) 要过程
先把右边的移到左边(x-5)\/(x+7)-(x-3)\/(x-5)+(x-2)\/(x-4)-(x-4)\/(x-6)=0 再通分,得[(x-5)(x-5)-(x-3)(x-5)]\/[(x+7)(x-5)]+[(x-2)(x-4)-(x-4)(x-4)]\/[(x-4)(x-6)]=0 再整理,可得-2\/(x+7)+2\/(x-6)=0 即2\/(x+7)=2\/(x-6)
数学解方程(x\/x-2)+(x-9\/x-7)=(x+1\/x-1)+(x-8\/x-6)
x-8\/(x-6)=1-2\/(x-6) 代入得1\/(x-2)-1\/(x-7)=1\/(x-1)-1\/(x-6) 移项得1\/(x-2)+1\/(x-6)=1\/(x-1)+1\/(x-7) 然后通分就好算了,注意x不等于1,2,6,7(分母不为0),最后要作为增根消去. 2.方法类似上一题,都是先写成1+一个分数的形式,然后移项后再通分 ...
解:(x-2分之x)+(x-7分之x-9)=(x-1分之x+1)+(x-6分之x-8)
x\/(x-2)+(x-9)\/(x-7)=(x+1)\/(x-1)+(x-8)\/(x-6)(x-2+2)\/(x-2)+(x-7-2)\/(x-7)=(x-1+2)\/(x-1)+(x-6-2)\/(x-6)1+2\/(x-2)+1-2\/(x-7)=1+2\/(x-1)+1-2\/(x-6)1\/(x-2)+1-1\/(x-7)=1\/(x-1)-1\/(x-6)[x-7-(x-2)]\/[(x-1)(x...
解方程:(x-1)\/(x-2)-(x-3)\/(x-4)=(x-2)\/(x-3)(x-4)\/(x-5)
(x-5)通分后多项式乘多项式: (x2-5x+4-(x2-5x+6))\/(x-2)(x-4)=(x2-7x+10-(x2-7x+12))\/(x-3)(x-5)整理:-2\/(x-2)(x-4)=-2\/(x-3)(x-5)得到:(x-2)(x-4)=(x-3)(x-5)多项式乘多项式: x2-6x+8=x2-8x+15 解得:x=3.5 最后分式方程要检验 ...
解方程(x-1\/x-2) -(x-3\/x-4)=(x-2\/x-3)-(x-4\/x-5)
很简单吧。例如(x-1)\/(x-2)=1- 1\/(x-2)将这四项都这么变形,原方程变为 1\/(x-4) -1\/(x-2)=1\/(x-5)-1\/(x-3)两边通分,得1\/(x-2)(x-4)=1\/(x-5)(x-3)所以(x-2)(x-4)=(x-3)(x-5)拆开得-6x+8=-8x+15 解得x=3.5 ...