大家回答我一个问题啊 ，，帮我解决一下啊。。 用C语言实现一个编程。。重建盘中输入一个任意的多位整数（

Question

大家回答我一个问题啊 ，，帮我解决一下啊。。 用C语言实现一个编程。。重建盘中输入一个任意的多位整数（位数不确定）将每一位之间多用一个分隔符￥隔开之后输出。。
注意:最后一个书不能是分隔符号
列如输入为：12345 那么输出就是1￥2￥3￥4￥5

Answer 1

#include <stdio.h>

main()
{
char* str1,str2;
int i = 0,j = 0,temp=0;
printf("输入数字串：");
scanf("%s",str1);
while(str1[i] != '\0')
{
if((int)str1[i] <= 48 && (int)str1[i] >= 57)
{
printf("输入的串存在非数字");
return 0;
}
}
do
{
str2[j++] = str1[i++];
str2[j++] = '￥';
}
while(str1[i] != '\0');

str2[--j] ='\0';

printf("输出数字串：%s",str2);
scanf("%d",&temp);

}

Answer 2

#include <stdlib.h>
#include <stdio.h>
#include <string.h>

/*
* === FUNCTION ======================================================================
* Name: main
* Description: input big number and return string sep each num with a ￥
* =====================================================================================
*/
int main ( int argc, char *argv[] )
{
const int numSize = 256;
char longNum[numSize];
int i,len;
while( scanf("%s", longNum) == 1 ){
len = strlen(longNum);
if('0' > longNum[0] || '9' < longNum[0]){
printf("Your input is not correct,Make sure it's a number, Try again!\n");
continue;
}

printf("%c", longNum[0]);
for(i=1; i<len; i++){
if('0' > longNum[i] || '9' < longNum[i]){
printf("\rYour input is not correct,Make sure it's a number, Try again!\n");
break;
}
printf("￥%c", longNum[i]);
}
printf("\n");
}
return EXIT_SUCCESS;
} /* ---------- end of function main ---------- */

Answer 3

#include<stdio.h>
#include<math.h>
void main()
{
unsigned int num; //输入一个小于4294967295的整数
unsigned int i, k=1, temp,a[32];

printf("Please input a number ：\n");
scanf("%d",&num);

temp =num;
while(temp/10)
{
a[k-1] = temp % 10;
temp /= 10;
k++;
}

a[k-1] = temp % 10;
for (i=0;i<k;i++)
{
printf("%d￥",a[k-1-i]);
}
printf("\n");
}
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