已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)

如题所述

第1个回答  2019-12-21
2sin(x-π/4)sin(x+π/4)=cos(x-π/4-x-π/4)-cos(x-π/4+x+π/4)=-cos2x
f(x)=cos(2x-π/3)-cos2x=cos(2x-π/6-π/6)-cos(2x-π/6+π/6)=2sin(2x-π/6)sin(π/6)=sin(2x-π/6)
最小正周期是2π/2=π,图象对称轴很容易知道是π/3+nπ/2

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已知函数f(x)=cos(2x-π\/3)+2sin(x-π\/4)sin(x+π\/4) 求函数f(x
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已知函数f(x)=cos(2x-π\/3)+2sin(x-π\/4)sin(x+π\/4)
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已知函数为f(x)=cos(2x-π╱3)+2sin(x-π\/4)sin(x+π\/4)
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2x)=√3sin(2x-π\/3)1. 可见,f(x)最小正周期为2π\/2=π 图像为g(x)=√3sin(2x)向右平移π\/6个单位得到 则对称轴为,x=kπ\/2+5π\/12(k∈Z)2. 令z=2x-π\/3 由x∈[-π\/12,π\/2]则z∈[-π\/2,2π\/3]√3sin z∈[-√3,√3]即f(x)值域为[-√3,√3]

已知函数f(x)=cos(2x-pai\/3)+2sin(x-pai\/4).sin(x+pai\/4)求函数在区...
f(x)=cos(2x-π\/3)+2sin(x-π\/4)cos[π\/2-(x+π\/4)]=cos(2x-π\/3)+2sin(x-π\/4)cos(π\/4-x)=cos(2x-π\/3)+2sin(x-π\/4)cos(x-π\/4)=cos(2x-π\/3)+sin(2x-π\/2)=cos(2x-π\/3)-cos2x =(1\/2)cos2x+(√3\/2)sin2x-cos2x =(√3\/2)sin2x-(1\/2)cos...

已知函数f(x)=cos(2x-3\/派)+2sin(x-4\/派)sin(x+4\/派)1。求f(x)的最...
得 原式=2sin (2x-派\/6)sin (派\/6)=sin (2x-派\/6)周期T=2派\/2=派,对称轴:2x-派\/6=派\/2+k派 (k属于整数)x=派\/3+k派\/2 (k属于整数)因为函数 f(x)在-派\/6到派\/3为单调增函数 所以函数 f(x)在-派\/12到派\/2上的值域为:[-根号3\/2,1]...

已知函数f(x)=cos(2x-π\/3)+2sin(x-π\/4)sin(x+π\/4)
2sin(x-π\/4)sin(x+π\/4)=cos(x-π\/4-x-π\/4)-cos(x-π\/4+x+π\/4)=-cos2x f(x)=cos(2x-π\/3)-cos2x=cos(2x-π\/6-π\/6)-cos(2x-π\/6+π\/6)=2sin(2x-π\/6)sin(π\/6)=sin(2x-π\/6)最小正周期是2π\/2=π,图象对称轴很容易知道是π\/3+nπ\/2 ...

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