ORACLE数据库存储过程，转义符问题

Question

我要的存储过程的SQL语句是：
delete from new_report_data t,new_user_id u
where t.user_id_index=u.user_id_index
and u.user_id_name in
('46cb80f2d77ce8f66cfb989e64bc0b61','445cefe016ee6a0f55856e0cac86aff0',
'103af1d15234daba68adb990cd42dc89','1dee142a8f7c268a47ec85c420712961',
'c7140a97b0d12c5125d7d8709174cd58','b9231c759be355ec90efc2e487f4435a',
'badc5300a4283f9b707487591c939987','206096931dcf537976fbe141faef55f4')

下面我创建了一个存储过程，建立的时候没有语法错误，但执行的时候出现了错误，是转义符搞错了吗？怎么改？
create or replace procedure delete_new_report_data
as
sql_de1 varchar2(200);
begin
sql_de1:='delete from new_report_data t,new_user_id u
where t.user_id_index=u.user_id_index
and u.user_id_name in
(''46cb80f2d77ce8f66cfb989e64bc0b61'',''445cefe016ee6a0f55856e0cac86aff0'',
''103af1d15234daba68adb990cd42dc89'',''1dee142a8f7c268a47ec85c420712961'',
''c7140a97b0d12c5125d7d8709174cd58'',''b9231c759be355ec90efc2e487f4435a'',
''badc5300a4283f9b707487591c939987'',''206096931dcf537976fbe141faef55f4'')
';
EXECUTE IMMEDIATE sql_de1;
COMMIT;
end;

Answer 1

sql_de1 varchar2(200)  中 200之 太小了，超出delete 语句的长度，将其改为 sql_de1 varchar2(2000)

Answer 2

是你第三行变量的长度定义的不够长吧，改为500试一下
sql_de1 varchar2(500);