=[cos(4x+2π/3)+1]/2-[1-cos(4x+2π/3]/2
=cos(4x+2π/3)
所以T=2π/4=π/2
解析：运用原理2cos²x-1=cos2x和1-2sin²x=cos2x本回答被提问者采纳
求y=cos(2x+π\/2)sin(2x+π\/2)的导数
y=cos²(2x+π\/3)-sin²(2x+π\/3)=[cos(4x+2π\/3)+1]\/2-[1-cos(4x+2π\/3]\/2 =cos(4x+2π\/3)所以T=2π\/4=π\/2 解析：运用原理2cos²x-1=cos2x和1-2sin²x=cos2x
怎样用最简单的方法求: xcos(2x+兀\/2)sin(2x+兀\/2)的导数?
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函数y=xsin(2x-π\/2)cos(2x+π\/2)的导数是?
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求函数y=xsin(2x-π\/2)cos(2x+π\/2)的导数?,要过程,最好是图
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sin²x的n阶导数怎么求?
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设fx=sin兀\/2+cos( 2x),则f(0)的n阶导数等于多少?
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