C#程序设计？自定义一个时间类，该类包含时，分，秒字段与属性，具有将时间增加1秒，1分，1小时的方法，具

Question

C#自定义一个时间类，该类包含时，分，秒字段与属性，具有将时间增加1秒，1分，1小时的方法，具有分别显示时，分，秒同时显示时分秒的方法

Answer 1

class MyDate
{
int hour;

public int Hour
{
get { return hour; }
set { hour = value; }
}
int min;

public int Min
{
get { return min; }
set { min = value; }
}
int sec;

public int Sec
{
get { return sec; }
set { sec = value; }
}

public DateTime AddSecond()
{
return DateTime.Now.AddSeconds(1);
}

public DateTime AddMin()
{
return DateTime.Now.AddMinutes(1);
}

public DateTime AddHour()
{
return DateTime.Now.AddHours(1);
}

public string ShowSecond()
{
return DateTime.Now.Second.ToString();
}
public string ShowMin()
{
return DateTime.Now.Minute.ToString();
}
public string ShowHour()
{
return DateTime.Now.Hour.ToString();
}
public string ShowAll()
{
return DateTime.Now.Hour.ToString() +":"+ DateTime.Now.Minute.ToString() +":"+ DateTime.Now.Second.ToString();
}
}

本人纯手写，原创答案

Answer 2

你的描述不够具体,所以不知道这个写的合不合适,只是根据你的大体意思写的
/// <summary>
/// Time 的摘要说明
/// </summary>
public class Time
{
//无参构造方法
public Time() { }
//有参构造方法
public Time(int hour, int minute, int second)
{
this.Hour = hour;
this.Minute = minute;
this.Second = second;
}

//时
private int hour;
public int Hour
{
get { return hour; }
set { hour = value; }
}

//分
private int minute;
public int Minute
{
get { return minute; }
set { minute = value; }
}

//秒
private int second;
public int Second
{
get { return second; }
set { second = value; }
}

//把时分秒都加1
public void AddAll(int hour, int minute, int second)
{
hour += 1;
minute += 1;
second += 1;
}
//显示时
public string ShowHour(int hour)
{
return hour.ToString();
}
//显示分
public string ShowMinute(int minute)
{
return minute.ToString();
}
//显示秒
public string ShowSecond()
{
return second.ToString();
}
/// <summary>
/// 显示时分秒的方法
/// </summary>
/// <param name="hour"></param>
/// <param name="minute"></param>
/// <param name="second"></param>
/// <returns></returns>
public string ShowAll(int hour, int minute, int second)
{
return hour.ToString() + ":" + minute.ToString() + ":" + second.ToString();
}
}