用c语言编程实现“有一个字符串,今输入一个字符,将字符串中该字符删掉”

Answer 1

#include <stdio.h>
main()
{ char *str,ch;
int i,n,j;
printf("Please input a string:");
scanf("%s",str);
printf("\nPlease input a character:");
scanf("%c",&ch);
i=0;n=strlen(str);
while(*(str+i)&&(i<=n))
{ if (*(str+i)==ch)
{ for(j=i;*(str+j);j++) *(str+j)=*(str+j+1);
n--;
}
i++;
}
printf("%s",*str);
}

Answer 2

#include<stdio.h>
#include<string.h>
void main()
{char s[80];
char ch;
int i,len=0;
ch=getchar();
gets(s);
len=strlen(s);
while(ch!=s[i]&&s[i]!='\0')
i++;
if(i>=len)
printf("Not found");
else {
while(s[i]!='\0')
{s[i]=s[i+1];
i++;}}
}

Answer 3

const char* szSrc ="Hello the Word!";
char szChar ='o';

char* szTag = new char[strlen(szSrc)];
int nTagLen = 0;

for (int i =0;i<strlen(szSrc);i++)
{
if (szSrc[i] != szChar)
{
szTag[nTagLen]=szSrc[i];
nTagLen++;
}
}
szTag[nTagLen]='\0';

//不在使用szTag
delete []szTag;

Answer 4

#include<stdio.h>
void Delete( char a[] , int n , char del )
{
int i,j;
for( i = 0 ; i < n ; i++ )
{
if(a[i]==del)
{
for(j = i ; j < n ;j++)
{
a[j] = a[j+1];
}
i--;
}
}
}

int main()
{
char s[10000],c;
while( gets(s) )
{
c = getchar();
Delete( s, strlen(s) , c );
puts(s);
gets(s);
}
return 0;
}