求通达信里面五，十。二十均线多头排列，MACD，KDJ金叉的选股公式

Question

只要MACD里面的DIF>DEA, KDJ里面的J>K>D就行

Answer 1

{详细一点就这样：}
MA5:=MA(CLOSE,5);
MA10:=MA(CLOSE,10);
MA20:=MA(CLOSE,20);
DIF:=EMA(CLOSE,12)-EMA(CLOSE,26);
DEA:=EMA(DIF,9);
AA:=CROSS(DIF,DEA);
RSV:=(CLOSE-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K:=SMA(RSV,3,1);
D:=SMA(K,3,1);
J:=3*K-2*D;
BB:=CROSS(J,K);
XG:MA5>MA10 AND MA10>MA20 AND AA AND BB;
------------------------------------------------------------------
{简写就这样：}
MA5:=MA(CLOSE,5);
MA10:=MA(CLOSE,10);
MA20:=MA(CLOSE,20);
XG:MA5>MA10 AND MA10>MA20 AND CROSS( "MACD.DIF ","MACD.DEA") AND CROSS("KDJ.J","KDJ.K") ;

Answer 2

一大乔，二小乔，三寸金莲四寸腰，五匣六盒七彩纷，八分九分十信娇。（求下联）答案：上联：一大乔，二小乔，三寸金莲四寸腰，五匣六盒七彩纷，八分九分十信娇。下联：十九月，八分圆，七个进士六个还，五更四鼓三声向，二乔大乔一人占。

Answer 3

这么好的公式不跟分，谁给你做呢？

追问

给分了

追答

我只是给你出个给分的注意！祝福你好运，我原来给了100
分要个多头排列的都没有

Answer 4

今天太晚了,明天上午写吧

Answer 5

ma(c,5)>ma(c,10) and ma(c,10)>ma(c,20) and ma(c,5)>ref(ma(c,5),1) and ma(c,10)>ref(ma(c,10),1) and ma(c,20)>ref(ma(c,20),1) and "macd.dif">"macd.dea" and "kdj.j">"kdj.k" and "kdj.k">"kdj.d";