lim(x→0)[xln(1-x^2)+6(x-sinx)]/x^5

Question

lim(x→0)[xln(1-x^2)+6(x-sinx)]/x^5

Answer 1

=lim(ln(1-x²)+x(-2x/(1-x²)+6-6cosx)/5x^4
=lim(-2x/(1-x²)-2*2x/(x²-1)²+6sinx)/20x³
=lim(x³-3x+3sinx(x²-1)²)/10x³lim1/(x²-1)²
=lim(3x²-3+3cosx(x²-1)²+3sinx2(x²-1)2x)/30x²
=lim(x²-1)(1+cosx(x²-1)+4xsinx)/10x²
=-lim(-2sin²(x/2)+x²cosx+4xsinx)/10x²
=-lim(-

追答

=-9/20

追问

可答案是-11/20啊？

可答案是-11/20啊？

追答

有3应该是-9/20

追问

什么有3？

什么有3？