c#中怎样将16进制转换成十进制？

Answer 1

1、Convert.ToInt32("FF", 16)\x0d\x0a2、如果转换的数值太大防止溢出也可Convert.ToInt64("数值", 16)\x0d\x0a3、第三种\x0d\x0a///

\x0d\x0a/// 十六进制换算为十进制\x0d\x0a///

\x0d\x0a/// \x0d\x0a/// \x0d\x0apublic static int GetHexadecimalValue(String strColorValue)\x0d\x0a{\x0d\x0achar[] nums = strColorValue.ToCharArray();\x0d\x0aint total = 0;\x0d\x0atry\x0d\x0a{\x0d\x0afor (int i = 0; i < nums.Length; i++)\x0d\x0a{\x0d\x0aString strNum = nums[i].ToString().ToUpper();\x0d\x0aswitch (strNum)\x0d\x0a{\x0d\x0acase "A":\x0d\x0astrNum = "10";\x0d\x0abreak;\x0d\x0acase "B":\x0d\x0astrNum = "11";\x0d\x0abreak;\x0d\x0acase "C":\x0d\x0astrNum = "12";\x0d\x0abreak;\x0d\x0acase "D":\x0d\x0astrNum = "13";\x0d\x0abreak;\x0d\x0acase "E":\x0d\x0astrNum = "14";\x0d\x0abreak;\x0d\x0acase "F":\x0d\x0astrNum = "15";\x0d\x0abreak;\x0d\x0adefault:\x0d\x0abreak;\x0d\x0a}\x0d\x0adouble power = Math.Pow(16, Convert.ToDouble(nums.Length - i - 1));\x0d\x0atotal += Convert.ToInt32(strNum) * Convert.ToInt32(power);\x0d\x0a}\x0d\x0a\x0d\x0a}\x0d\x0acatch (System.Exception ex)\x0d\x0a{\x0d\x0aString strErorr = ex.ToString();\x0d\x0areturn 0;\x0d\x0a}\x0d\x0a\x0d\x0areturn total;\x0d\x0a}