设y=1n3x-cos5x,求dy

如题所述

第1个回答  2015-07-12
dy=3*(1/3*x)+5sin5x

设y=1n3x-cos5x,求dy
y=ln3x-cos5x dy={3\/(3x)+5sin5x}dx = {1\/x + 5sin5x}dx

设y=1n3x-cos5x,求dy
dy=3*(1\/3*x)+5sin5x

设y=1n3x—cos5x 求dy
解:y'=(ln3X - cos5X)'=3x(1\/3X)-【5x (-sin5X)】=1\/X+5sin5X 注:x为乘号 X为英文“埃克斯”

设y=1n3x一cos5x求dy
y=ln3x-cos5x dy={3\/(3x)+5sin5x}dx = {1\/x + 5sin5x}dx

y=ln3x-cos5x,求dy
y=ln3x-cos5x,求dy dy=3\/x-5sinx

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