编写程序,用while循环计算f=1/2+1/4+1/6+1/8+......+1/1000的值？

Answer 1

#include <stdio.h>

int main()

{

double f=0,i=2;

while(i<=1000)

{

f+=1.0/i;

i+=2;

}

printf("%lf\n",f);

return 0;

}

Answer 2

PHP 版的
12345678<?php$i = 2; $j = 1;do{ $j += 1 / $i; $i += 2; } while($i <= 100);echo $j;

Answer 3

float n = 1;
float f = 0;
while(n<=500)
{
f+=1/(2*n);
n++;
}
print("%f",f);