用表格形式显示ASCII字符SMASCII的程序是什么

Question

要求：按15行*16行的表格形式显示ASCII码为10H－100H所有字符，即以行为主的顺序及ASCII码递增的顺序依次显示对应的字符，每16个字符为一行，每行中的相邻两个字符间用空白符（ASCII为0）隔开

Answer 1

#include <stdio.h>
#include <stdlib.h>
FILE *fout;
void main (int argc, char *argv[])
{
char nameout[72];
int i,j,k=0;

strcpy(nameout,"ASCII_TABLE.TMP");
if ( (fout = fopen(nameout,"wb") ) == NULL ) {
printf("\007Cann't open output file: %s ", nameout);exit(1);
};

k = 0;
for (j= 0x10; j <= 0x100 ;j=j+1) {
// check: fprintf(fout,"%03x ",j);
fputc(j,fout); fprintf(fout," ");
k = k + 1;
if ( k % 16 == 0) fprintf(fout,"\n");
};
fclose(fout);
printf("Output in %s\n", nameout);
exit(0);
}

用MS VC++ 编译器编译并试验了，程序正确。