=1/(3-x)*(x+2)(x-2)/(x+1)^2
=(x+2)(x-2)/(x+1)^2(3-x)
=5/24
...再求值:(1-x+2分之1)除以x的平方-4分之x的平方+2x+1,其中x=-3
1\/(1-x+2)\/(x^2+2x+1)\/(x^2-4)，其中x=-3 =1\/(3-x)*(x+2)(x-2)\/(x+1)^2 =(x+2)(x-2)\/(x+1)^2(3-x)=5\/24
...再求值:(1-x+2分之1)除以x的平方-4分之x的平方+2x+1,其中x=-3
1\/(1-x+2)\/(x^2+2x+1)\/(x^2-4),其中x=-3 =1\/(3-x)*(x+2)(x-2)\/(x+1)^2 =(x+2)(x-2)\/(x+1)^2(3-x)=5\/24
(1+X-2分之1)÷X的平方-4分之X平方-2X+1其中X=5先化简在求值
=(x-1)*[4-(x-1)(x-2)x²]\/4(x-2)x²=4*[4-4*3*25]\/4*3*25 =-296\/75 要是（1+X-2分之1）÷（X的平方-4分之X平方-2X+1）=(x-2+1)\/(x-2)÷[(x-1)²-x²\/4]=(x-1)\/(x-2)÷[(x-1-x\/2)(x-1+x\/2)]=(x-1)\/(x-2)÷[(...
先化简再求值:x+2分之1-x^2-x分之x^2-4x+4÷(x+1-x-1分之3),其中x是...
=(x^2-4)(x-x+2)\/(x^2-4)(x^2+2x)=2\/(x^2+2x)x=3 时，原式=2\/(3^2+2*3)=2\/(9+6=2\/15
先化简,再求代数式(1-x+2分之3)除以x+2分之x的平方-1的值,其中x是不等...
已知，X+3>=0且2X+9<8,分别求两个不等式得，X>=（-3）且X<（-1\/2),又X是整数解，所以X可能的值有：-3，-2，-1 。然后，分别把-3，-2，-1代入题目“代数式(1-x+2分之3)除以x+2分之x的平方-1的值”，即可计算出结果 望采纳 ...
先化简,再求值(x^2-1分之3x+4-x-1分之2)÷x^2-2x+1分之x+2 其中x=-3
原式 =[(3x+4)\/(x-1)(x+1) - 2\/(x-1) ] * (x-1)²\/(x+2)=(3x+4-2x-2)\/(x+1) * (x-1)\/(x+2)=(x-1)\/(x+1)x=-3 原式=(x-1)\/(x+1)=(-3-1)\/(-3+1)=2
先化简再求值x+2分之1-x+2分之x的平方+2x+1除以x-1分之x的平方-1其中x...
原式=[1\/(x+2)]-[(x+2x+1)\/(x+2)]÷[(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷[(x+1)(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷(x+1) =[1\/(x+2)]-[(x+1)\/(x+2)]×[1\/(x+1)] =[1\/(x+2)...
先化简再求值x+2分之1-x+2分之x的平方+2x+1除以x-1分之x的平方-1其中x...
原式=[1\/(x+2)]-[(x+2x+1)\/(x+2)]÷[(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷[(x+1)(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷(x+1) =[1\/(x+2)]-[(x+1)\/(x+2)]×[1\/(x+1)] =[1\/(x+2)...
先化简,再求值:x-1\/x+2*x^2-4\/x^2-2x+1\/1\/x^2-1 其中x=1
1、（x-1\/x+2）*2（x^2-4\/x^2-2x+1）+(1\/x-1)=(x-1\/x+2)*2[(x-2)(x+2)\/(x-1)(x-1)]+(1\/x-1)=2(x-2)\/(x-1)+(1\/x-1)= 2x-4+1\/x-1 =2x-3\/x-1 x=1不可以，会导致分母为零，无意义的！
先化简 再求值 (1-x+2分之1)除于x+2分之x的2次方-1, 其中X=2
（1-x+2分之1）除于x+2分之x的2次方-1 =(1-x+1\/2)\/x+(x²-1)\/2 =(3\/2-x)\/x+(x²-1)\/2 =3\/2x-1+x²\/2-1\/2 =x²\/2+3\/2x-3\/2 x=2;原式=4\/2+3\/(2×2)-3\/2=2+3\/4-3\/2=5\/4;...
