#include <stdio.h> int exchange( int a, int b ) { int temp; temp = a; a = b; b = temp; return( a, b

Question

哪里出问题了？？
#include <stdio.h>

int exchange( int a, int b )
{
int temp;

temp = a;
a = b;
b = temp;
return( a, b );

}

int main()
{
int x, y, z;
printf( "please input three integers:\n" );
scanf( "%d%d%d", &x, &y, &z );

if( x > y )
exchange( x, y );
if( x > z )
exchange( x, z );
if( y > z )
exchange( y, z );

printf( "%d %d %d", x, y, z );

return(0);
}

Answer 1

函数的参数改一改就可以了。

#include <stdio.h>

void exchange( int *a, int *b )
{
int temp;

temp = *a;
*a = *b;
*b = temp;
return;

}

int main()
{
int x, y, z;
printf( "please input three integers:\n" );
scanf( "%d%d%d", &x, &y, &z );

if( x > y )
exchange( &x, &y );
if( x > z )
exchange( &x, &z );
if( y > z )
exchange( &y, &z );

printf( "%d %d %d", x, y, z );
getch();

return(0);
}

Answer 2

因为C调用时不支持值的传递。虽然你调用函数将值改变了，但它并不影响x,y,z的值;
你可以用数组和指针重新调用函数，就能将功能实现！