c语言sum=1+2+3+4+…+n写出程序
\/* Note:Your choice is C IDE *\/ #include "stdio.h" main() { int sum=0,n=100,i; for(i=1;i<=n;i++) sum+=i; printf("sum=%d\\n",sum); }
编程1+2+3+4...+n的值超过500的第一和值为多少?n的值为多少?
int main(void){ int x;int sum = 1;for (x = 2;x < 500;x++){ sum = sum + x;if (sum > 500){break;} } printf("当和大于500时的第一和值为：");printf("%d\\n",sum);printf("当和大于500时N的值是：");printf("%d\\n",x);getch();} ...
用c语言函数求1!+2!+3!+4!+……n!
int fac(int n){ if(n<2)return 1;else return n*fac(n-1);}
1+2+3+4...+n=5050求n的值 c语言
include <iostream>#include <string>using namespace std;int main(){ int a, sum; sum = 0; for (a==1; sum >= 0;a++) { sum = sum+a; if (sum >= 5050) break; } cout << a << endl;}sum 应该大于等于0 ...
用C语言设计一个程序,求1!+2!+3!+4!+5!+…+n!
int 0<n<13)...\\nn="); if(scanf("%d",&n),n<0 || n>12){ printf("Input error, the program exits...\\n"); exit(0); } for(sum=0,t=i=1;i<=n;sum+=t*=i++); printf("The result is %d\\n",sum); return 0;} ...
用C语言解决1+2+3+4+? 的问题
int sum(int n){ int s=0; while(n>0) { s+=n; n--; } return(s);}
C语言编写程序,求1+2+3+4+……..+100的和
include "stdio.h"int sum(int n){ int sum =0 ;for (int i =0;i<=n;i++){ sum +=n;} return sum;} void main(void){ int sum =0;sum =sum (100);printf("sum is %d",sum);}
c语言中如何输出1+2+3+4+……(输出的不是最后的值)
include<stdio.h>void main() { int i,s,n; scanf("%d",&n); s=0; for ( i=0;i<n;i++ ) { if ( i==0 ) printf("%d",i+1); else printf("+%d",i+1); s+=i+1; } printf("=%d\\n",s);}
初级C语言:求1+2+3+……+n≤m时的最大n值及和sum
参考代码如下：include <stdio.h> int main(){ int sum=0,m,i=1;scanf("%d",&m);while(sum<=m){ sum+=i;i++;} printf("n=%d,sum=%d",i-1,sum-i);return 0;} 运行结果：
c语言用高精度方法,求s=1+2+3+4+……+n的精确值
{ int i=1;a[1]++;while(a[i]>9)a[i]-=10,a[i+1]++,i++;if(i>a[0])a[0]=i;} int main(){ int a[101]= {0},b[101]= {0},c[202]= {0};readint(a);b[0]=a[0]-(a[a[0]]==1);for(int i=a[0]; i>0; i--)b[i]=a[i]\/2+5*(a[i+1]%2)...
